What is the RMS voltage of a sine wave with a value of 17 volts peak?

8.5 volts

12 volts

The root mean square (RMS) voltage of a sine wave is a value that represents the effective voltage of the waveform. For a sine wave, the RMS voltage can be calculated from the peak voltage using the formula:

\[ V_{RMS} = \frac{V_{peak}}{\sqrt{2}} \]

In this case, the peak voltage provided is 17 volts. To find the RMS voltage, we apply the formula:

\[ V_{RMS} = \frac{17 \text{ volts}}{\sqrt{2}} \approx \frac{17}{1.414} \approx 12 \text{ volts} \]

This calculation shows that the RMS voltage of a sine wave with a peak value of 17 volts is approximately 12 volts, making it the correct answer.

The other choices do not correspond to this relationship derived from the standard formula for RMS voltage, indicating they do not accurately reflect the conversion from peak to RMS for a sine wave.

24 volts

34 volts

Want more questions?

All options are one-time payments.

$25.99

30 day premium pass

All the basics to get you started

  • Ad-free experience
  • View your previous attempt history
  • Mobile app access
  • In-depth explanations
  • 30 day premium pass access
$59.99 $171.99 usd

6 month DELUXE pass (most popular)

Everything with the 30 day premium pass FOR 6 MONTHS! & the ultimate digital PDF study guide (BONUS)

  • Everything included in the premium pass
  • $171.99 usd value for $59.99! You save $106!
  • + Access to the ultimate digital PDF study guide
  • + 6 months of premium pass access
  • + Priority support
$15.99 $24.99

Ultimate digital PDF study guide

For those that prefer a more traditional form of learning

  • Available for instant download
  • Available offline
  • Hundreds of practice multiple choice questions
  • Comprehensive content
  • Detailed explanations
Image Description
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy